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mrs_skeptik [129]
3 years ago
14

HELP ME WITH THIS PLEASE!!!!

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

The answer is left two places.

For example 5.% would be 0.05 as a decimal.

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Which equation matches the graph shown?
Kitty [74]

Answer:

f(x) = -(x+2)(x-1)

Step-by-step explanation:

We know the zeros are at 1 and -2

f(x) = a *(x-b1)(x-b2)  where b1 and b2 are the zeros and a is a constant

f(x) =a(x-1)(x- -2)

f(x) =a(x-1)(x+2)

We know that a must be negative since the parabola opens down so

The only choice is choice D where a = -1

f(x) = -(x+2)(x-1)

3 0
3 years ago
Erin’s car uses 6 gallons of gas for every 138 miles she drives. Which equation could be used to find how many gallons,g, Erin n
alina1380 [7]

Answer:

g = 6 / 3 x 2

Step-by-step explanation:

g = 6 / 3 x 2 because 92 / 2 = 46. 46 x 3 = 138. so / 3 = 46 x 2 = 92

3 0
1 year ago
0.3(4-x)=x-1.4 how do you solve this problem?
tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer:  x = 2.

4 0
3 years ago
Mona had some colored papers. The teacher gave her 12 more papers. she counted all the
timama [110]

Answer:

24

Step-by-step explanation:

really need more information about the subject, but im assuming its just basic addition.

36-12=24

8 0
3 years ago
What should be done to x^2 + 15x in order to create a perfect square?
lana [24]

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] ~\dotfill

\bf x^2+15x+\boxed{?}^2\implies \stackrel{\textit{we know the middle term is}}{2\sqrt{x^2}\cdot \sqrt{\boxed{?}^2}\implies 2x\boxed{?}}\qquad then\qquad 2x\boxed{?}=15x \\\\\\ \boxed{?}=\cfrac{15x}{2x}\implies \boxed{?}=\cfrac{15}{2}\qquad \impliedby \textit{we should add that much \underline{squared}} \\\\[-0.35em] ~\dotfill\\\\ x^2+15x+\left( \cfrac{15}{2} \right)^2\implies \left(x+ \cfrac{15}{2} \right)^2

5 0
3 years ago
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