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3 years ago

9

Denise gets paid $600 an hour plus $430 commission on her sales. If her paycheck this week was $700, how many hours did she work

?

1 answer:

lakkis [162]3 years ago

6 0

To me this this question really doesn’t make that much sense so the best possible answer would be 1 hr

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A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

3 years ago

Find the slope of the line segment that joints the points A(2, -8) and B(-1, 16)

Karo-lina-s [1.5K]

We need to use the Point slope formula to find the slope so we label
(2 , -8);(-1 , 16) subtract
x1 y1 x2 y2. y2-y1/x2-x1
16-(-8)/-1-2 = 24/-3 = -8
meaning the slope of this line is (-8)

8 0

3 years ago

17 gallons of water are used to completely fill 4 fish tanks. If each tank holds the same amount of water how many gallons will

Kay [80]

Each tank holds 4.25 gallons! 17/4 is 4.25 :) hope this helps!

6 0

3 years ago

Evaluate the expression 27/j for j=3

STALIN [3.7K]

27 divided by 3 (j) is 9. If j=3 then plug in 3 for the equation

3 0

3 years ago

Evaluate 4x3 + 4x when x = 3.

Drupady [299]

Answer:

24

Step-by-step explanation:

12 + 4(3)

24

8 0

3 years ago

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