a. There are four 5s that can be drawn, and 
ways of drawing any three of them. There are 
ways of drawing any three cards from the deck. So the probability of drawing three 5s is
In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of 
of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability 
of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of 
.
- - -
Note: 
is the binomial coefficient,
19,7,and 61 im not sure about the last one
Y=2x+6
(This is me filling space)
Answer:
9
Step-by-step explanation:
forget all this grammar,
let the number be x,
x = {18(15-12)} / 6
x = {18(3)} / 6
x= 54/6
x= 9
value is therefore 9
Answer:
Probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
Step-by-step explanation:
We are given that 20% of the candy produced are red. A random sample of 100 bags of Skittles is taken.
The distribution we can use here is;
~ N(0,1)
where, p = 0.20 and n = 100
Let 
= proportion of red candies in our sample
So, P( < 0.20) = P( < 
) = P(Z < 0) = 0.5
Therefore, probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
