Question

Physics student is dropped. If they reach the floor at a speed of 3.2 m/s, from what height did they fall?

Answer 1

Answer:

0.52 m

Explanation:

The motion of the studnet is an accelerated motion, with constant acceleration $g=9.8 m/s^2$ (acceleration of gravity) toward the ground. We can find the distance covered by the student (which is equal to the height from which he falls) by using the SUVAT equation:

$v^2 -u^2 = 2ad$

where

v = 3.2 m/s is the final speed

u = 0 is the initial speed

a = 9.8 m/s^2 is the acceleration

d is the distance covered

By re-arranging the equation, we find:

$d=\frac{v^2-u^2}{2a}=\frac{(3.2 m/s)^2-0}{2(9.8 m/s^2)}=0.52 m$