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lys-0071 [83]
3 years ago
11

What is the force acting on a 10kg object that accelerates from 5 m/s to 20 m/s in 5s?

Physics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

Option C

Explanation:

v= u + at

20 = 5 + a(5)

15= a(5)

a= 3 m/s²

Force = mass × acceleration

= 10 × 3

= 30 N

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A rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind
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Answer:

Answer  for the question is given in the attachment.

Explanation:

Download pdf
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3 years ago
In which direction does a bag at rest move when a force of 20 newtons is applied from the right? A. in the direction of the appl
-Dominant- [34]

The correct answer is A. In the direction of applied force. This is because acceleration occurs n the direction of applied force according to Newtons second law of motion which states that the acceleration of a body is directly proportional to the applied force and takes place in the direction of force.

5 0
3 years ago
Read 2 more answers
Can anyone help me with this question please​
JulsSmile [24]

Explanation:

V=u+at

where,

v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

  1. v=u+at = 6=2+a*2

6=2+2a

2a=6-2

2a=4

a=4/2 = 2

a =2

2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

=4+20

v=24m/sec

5.v=u+at

=5+8*10

=5+80

V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

these are your missing values

5 0
3 years ago
During a total lunar eclipse, where is the Moon located?
krok68 [10]

During a total lunar eclipse, the Moon located in the umbra. The answer is letter A. For a total lunar eclipse to occur, the Sun, Earth and Moon must be aligned in a straight line. The Earth’s umbra complete covers the Moon. The earth’s umbra is about 870,000 miles wide.

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3 years ago
how much power is needed to lift a box with a force of 780 newtons over a distance of 2 meters in 45 seconds
-BARSIC- [3]

Answer:

<h2>34.67 W</h2>

Explanation:

Power is the rate at which work is done and can be found by using the formula

p =  \frac{w}{t}  \\

p is the power in Watts (W)

w is the workdone in joules

t is time in s

but workdone = force × distance

From the question

force = 780 N

distance = 2 m

workdone = 780 × 2 = 1560 N

Since we now have the value of workdone we can find the power

We have

p =  \frac{1560}{45}  = 34.6666666... \\

We have the final answer as

<h3>34.67 W</h3>

Hope this helps you

3 0
2 years ago
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