As the chicken cooks (and if it doesn't directly touch the fire), energy goes through the chemical, radiant, then thermal stages respectively.
The charcoal fire releases chemical energy. The heat of the fire is radiant, and the thermal (heat) of the fire cooks the chicken.
<u>Given that:</u>
height (h) = ?
mass (m) = 2 Kg ,
Potential energy (P.E.) = 100 J ;
We know that P.E = m × g × h
100 J = 2 × 9.81 × h
h = (100) ÷ (2 × 9.81)
<em> h = 5.09 m</em>
If
SO3(g)
is removed from the following reaction, will the equilibrium shift to the left, shift to the right, or stay the same? Explain.
2SO2(g)+O2(g)⇋2SO3(g);ΔH
Explanation: The reaction shown in the question is a combination reaction between sulfur dioxide gas and oxygen gas, forming sulfur trioxide gas by the two gases combining into one product. The question's objective is to determine the direction in which the equilibrium will shift if sulfur trioxide is removed. Removing the products from the container during a reversible chemical reaction means that only the forward reaction will proceed right after the products are removed. Once more of the products are formed, the reverse reaction will start to occur.
But, when the product is removed, the system will compensate for the removal of the product by increasing the production of the product, which is done by increasing the rate of the forward reaction and shifting the equilibrium to the right.
Answer:
The value of smaller resistor is 248 Ω.
Explanation:
Voltage divider circuit is used to convert a higher voltage to a smaller voltage with the help of resistors which are connected in parallel.
As shown in the circuit, Vs is the source voltage, R₁ and R₂ are the two resistors and V₀ is the output voltage.
Applying KVL in the circuit, the output voltage is given by :
According to the problem, R₂ = 310Ω , V₀ = 5 V and Vs = 9 V. Substitute these values in the above equation.
R₁ = 248Ω
