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2 years ago

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Which particles in an atom are acted upon by the strong force? A. Electrons and neutrons B. Neutrons and protons O C. Protons an

d electrons D. Protons, neutrons, and electrons SUE w

1 answer:

BARSIC [14]2 years ago

6 0

$\large \sf \pmb{B) \: Neutrons \: and \: Protons}$

<em>Neutrons And Protons</em> is a particles in an atom and are acted upon by the strong force.

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An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra

slega [8]

Answer:

Part a)

$v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s$

Part b)

$E = 4.4 \times 10^{-13} J$

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

$m_1v_1 + m_2v_2 + m_3v_3 = 0$

$(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0$

$(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0$

$v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s$

Part b)

By equation of kinetic energy we have

$E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2$

$E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}$

$E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}$

$E = 4.4 \times 10^{-13} J$

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3 years ago

A steel drill making 180 rpm is used to drill a hole in a block of steel. The mass of the steel block and the drill is 180 g. If

SVETLANKA909090 [29]

Answer:

a) 37.8 W

b) 2 Nm

Explanation:

180 g = 0.18 kg

We can also convert 180 revolution per minute to standard angular velocity unit knowing that each revolution is 2π and 1 minute equals to 60 seconds

180 rpm = 180*2π/60 = 18.85 rad/s

We can use the heat specific equation to find the rate of heat exchange of the steel drill and block:

$\dot{E} = mc\Delta \dot{t} = 0.18*420*0.5 = 37.8 J/s$

Since the entire mechanical work is used up in producing heat, we can conclude that the rate of work is also 37.8 J/s, or 37.8 W

The torque T required to drill can be calculated using the work equation

$E = T\theta$

$\dot{E} = T\dot{\theta} = T\omega$

$T = \frac{\dot{E}}{\omega} = \frac{37.8}{18.85} = 2 Nm$

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3 years ago

A vehicle reaches a speed of 7.5 m/s over 15 seconds. What is its acceleration if it

denpristay [2]

$acceleration = \frac{velocity}{time} = \frac{7.5}{15} = 0.5ms^-^2$

So the answer is option b.

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3 years ago

The long tube that moves food from the mouth to the stomach is called the __________.

AnnyKZ [126]

A the esophaguses!!!!!

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2 years ago

Ryan is driving his car to band practice. His speed is 55 mph. Splat! A bug smashes against the windshield, and bug "guts" are e

MrRa [10]

Answer:

The answer is C.

Explanation:

Every point mass attracts every single other point mass by a force acting along the line intersecting both points. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between them. In magnitude, the force they apply each other is the same. Therefore, the force that the windshield exerts on the bug and the force that the bug exerts on the windshield are the same magnitude.

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3 years ago

Read 2 more answers