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Sever21 [200]
3 years ago
6

Why does a radical function with an even index only appear on one sode of the x-axis while a radical woth an odd index appears o

n both sides?
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.

Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.

Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

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I need help finding m
Dafna1 [17]

Answer:

<A = 27 degrees

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

Tan A = opp side / adj side

Tan A = 2/4

Tan A = 1/2

Taking the inverse tan of each side

tan^-1 ( tan A) = tan ^-1 (1/2)

A =26.56505118

Rounding to the nearest  degree

A = 27

5 0
2 years ago
Someone help me asap math 10
Ghella [55]

Answer:

x ≈ 25.4 Km

Step-by-step explanation:

Using the tangent ratio in the right triangle on the right

tan54° = \frac{opposite}{adjacent} = \frac{opp}{17} ( multiply both sides by 17 )

17 × tan54° = opp , thus

opp ≈ 23.4

-------------------------------------------

Using the cosine ratio in the right triangle on the left

cos23° = \frac{adjacent}{hypotenuse} = \frac{23.4}{x} ( multiply both sides by x )

x × cos23° = 23.4 ( divide both sides by cos23° )

x = \frac{23.4}{cos23} ≈ 25. 4 Km ( to the nearest tenth )

6 0
4 years ago
-3√45+3√20<br>SHOW HOW YOU GOT YOUR ANSWER​
Juli2301 [7.4K]

-3√45 + 3√20 = -3√(9 · 5) + 3√(4 · 5) =

= -3√(3² · 5) + 3√(2² · 5) =

= -3 · 3√5 + 3 · 2√5 =

= -9√5 + 6√5 = -3√5 ← the end

4 0
3 years ago
Help!!
Elza [17]

Answer:

(b)\ 2x - 9 = -1

(c)\ -2x + 12 = 4

(e)\ 2(x - 10) = -12

Step-by-step explanation:

Required

Which equals x = 4

(a)\ 2x + 6 = 2

Collect like terms

2x  = 2 - 6

2x  = -4

Divide both sides by 2

x = -2

(b)\ 2x - 9 = -1

Collect like terms

2x = -1 + 9

2x = 8

Divide both sides by 2

x = 4

(c)\ -2x + 12 = 4

Collect like terms

-2x =- 12 + 4

-2x =-8

Divide both sides by -2

x = 4

(d)\ 2(x + 2) = 10

Divide both sides by 2

x + 2 =5

Collect like terms

x = 5-2

x = 3

(e)\ 2(x - 10) = -12

Divide both sides by 2

x - 10 = -6

Collect like terms

x = 10 - 6

x = 4

Hence, the equations with the required solution are:

(b)\ 2x - 9 = -1

(c)\ -2x + 12 = 4

(e)\ 2(x - 10) = -12

3 0
3 years ago
Can someone help plz im giving brain ​
kenny6666 [7]

Answer:

for 20 the answer is B

Step-by-step explanation:

8 0
3 years ago
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