Answer: 128 inches
Step-by-step explanation:
let's start with the perimeter: the perimeter is the total length to the sides/edges of a shape.
since we're dealing with a rectangle, there will be 4 sides
two lengths & two widths
so 48+48+16+16=128 inches
The answer: a° = 180° - 62° = 118° , b° = 62° , c° = (180° - 62°) ÷ 2 = 59°
Ok done. Thank to me :>
No the point does not lie on the line.
Answer: 4 m
Step-by-step explanation:
Let the amount each dimension was increased by be x.
Now we can set up a equation.
(2+x)(4+x) = 48
8 + 2x + 4x + x^2 = 48
x^2 + 6x - 40 = 0.
We can factor the left side of the equation.
(x+10)(x-4) = 0.
Therefore, x equals either -10 or 4. Since you can't increase a dimension by a negative amount, x must equal to 4.
The given angles mean that line QT divides angle PQS.
<em>The measure of </em>
<em> is </em>
<em />
Given that:
![\angle PQS = 3x + 13](https://tex.z-dn.net/?f=%5Cangle%20PQS%20%3D%203x%20%2B%2013)
![\angle SQT = 6x -2](https://tex.z-dn.net/?f=%5Cangle%20SQT%20%3D%206x%20-2)
Since QT divides
;
The equation to calculate
is:
![\angle PQT = \angle PQS - \angle SQT](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%20%5Cangle%20PQS%20-%20%5Cangle%20SQT)
This gives
![\angle PQT = 3x + 13- (6x -2)](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%203x%20%2B%2013-%20%286x%20-2%29)
Open bracket
![\angle PQT = 3x + 13- 6x +2](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%203x%20%2B%2013-%206x%20%2B2)
Collect like terms
![\angle PQT = 13+2- 6x + 3x](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%2013%2B2-%206x%20%2B%203x)
![\angle PQT = 15- 3x](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%2015-%20%203x)
Hence, the measure of
is ![15- 3x](https://tex.z-dn.net/?f=15-%20%203x)
Read more about angles at:
brainly.com/question/13954458