The function is

.
This means that as we get from 1 to 2, we have the following values:

, and

.
Similarly, if we check x=3, we have

.
We can see that as x changes by 1 (with greater values), y increases by a factor of 12.
Answer: multiply by 12
Answer: No problem
Step-by-step explanation:
Answer:
(x - 1) x (5x + 4)
Step-by-step explanation:
5 x 2 – 4 = 6
5 x 4 – 4 = 16
6 x 2 – 11x – 4 = 56
5 x 2 – x – 4 = (x - 1) x (5x + 4)
There are a total of 8 balls
The probability of drawing a white ball is 4/8 on the first draw.
If you replace the ball then the probability will still be 4/8 for a white ball, since these events are independent of each other you multiply 4/8 x 4/8 = 16/64 or 1/4 then the probability of drawing at least 1 red ball with replacement is 1 - 1/4 = 3/4
Now without replacement:
the probability of drawing a white ball is 4/8 since you don't replace the ball then the probability of drawing a white ball the second time is 3/7 again multiply these two probabilities: 4/8 x 3/7 = 12/56 the the probability of drawing at least 1 red ball is 1- 12/56 = 44/56 or 11/14
Answer:
A.(-2, 0)
C. (-1.4)
Step-by-step explanation:
we know that
If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)
we have

subtract 7 both sides


divide by 2 both sides

Substitute the value of x and the value of y of each point in the linear equation and analyze the result
<u><em>Verify each point</em></u>
case A) we have
(-2, 0)
For x=-2, y=0
substitute

---> is true
so
the point lie on the line
case B) we have
(1, 3)
For x=1, y=3
substitute

---> is not true
so
the point not lie on the line
case C) we have
(-1, 4)
For x=-1, y=4
substitute

---> is true
so
the point lie on the line
case D) we have
(1, -4)
For x=1, y=-4
substitute

---> is not true
so
the point not lie on the line
case E) we have
(0, -1)
For x=0, y=-1
substitute

---> is not true
so
the point not lie on the line