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3 years ago

What inequality is shown

Mathematics

2 answers:

VMariaS [17]3 years ago

3 0

Answer:

Y ≤ X + 6

Step-by-step explanation:

Not sure if this is correct

Vikentia [17]3 years ago

3 0

Answer:

y<1/5x+6

Step-by-step explanation:

< bcs below line

dotted line means not equal(≤)

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A rectangular field on a farm is to be fenced in using the wall of the barn for one side and 200 meters of fencing for the other

vitfil [10]

Answer:

Rectangular area as a function of x : A(x) = 200*x + 2*x²

A(max) = 5000 m²

Dimensions:

x = 50 m

l = 100 m

Step-by-step explanation:

"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:

A(r) = x* l and the perimeter of the rectangular shape is

P = 2*x + 2*l but we won´t use any fencing material along the wll of the barn therefore

P = 2*x + l ⇒ 200 = 2*x + l ⇒ l = 200 - 2*x (1)

And the rectangular area as a function of x is:

A(x) = x * ( 200 - 2*x) ⇒ A(x) = 200*x + 2*x²

Taking derivatives on both sides of the equation we get:

A´(x) = 200 - 4*x ⇒ A´= 0

Then 200 - 4*x = 0 ⇒ 4*x = 200 ⇒ x = 50 m

We find the l value, plugging the value of x in equation (1)

l = 200 - 2*x ⇒ l = 200 - 2*50 ⇒ l = 100 m

A(max) = 100*50

A(max) = 5000 m²

3 0

3 years ago

Three of every 5 pizzas that miggys pizza sels are cheese pizza miggys slod 80 pizza today how many of them would you expect wer

True [87]

48 of the pizzas would be cheese because you divide 80 by 5 and get 16 then multiply that by 3 to get 48

7 0

3 years ago

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$