Well the 2 in the tens place is ten times as many as the 2 in the hundreds place.Also the 5 in the thousand place is 10 times as many as the 5 in the ten thousand place
3,000 feet i think since the formula is width *height *length so it should be correct.
Answer and Step-by-step explanation:
-6 and -10 are the answers.
This is because these numbers are less than -5, so they would work when plugged in for h in the inequality.
<u><em>#teamtrees #PAW (Plant And Water)</em></u>
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
We can solve for the arc length using the formula shown below:
Arc Lenght = 2pi*r(central angle/360)
We need to convert the central angle such as:
Central angle = 23pi rad * (180°/pi rad) = 23*180
Radius = 24cm
Solving for arc length:
Arc length = 2*3.14 *24*(23*180/360)
Arc length = 1733.28 cm
