A=600⋅(1.0001)^365t
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Answer:
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
μ of the time a group of boys run the mile in its secondary- school fitness test = 440 seconds
σ of the time a group of boys run the mile in its secondary- school fitness test = 40 seconds
2. Find the probability that a randomly selected boy in school can run the mile in less than 348 seconds.
Let's find out the z-score, this way:
z-score = (348 - 440)/40
z-score = -92/40 = -2.3
Now let's find out the probability of z-score = -2.3, using the table:
p (-2.3) = 0.0107
p (-2.3) = 0.0107 * 100
p (-2.3) = 1.1% (rounding to the next tenth)
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,
y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
The answer to 41 divided by 8,928 would be 0.0046
