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il63 [147K]
3 years ago
11

5 pizza cost $60. What will 9 cost

Mathematics
1 answer:
zlopas [31]3 years ago
5 0
$540 dollars because 9times 60

You might be interested in
Solve for x: -5/6x= -10/3 x=?
k0ka [10]

Answer:

Solve for x: -5/6x= -10/3 x=?

x = 1/4

Step-by-step explanation:

from the equation ,Solve for x: -5/6x= -10/3 , to solve for x  we will first cross multiply

we have; -15= -60x

divide both sides by -60

-15/-60 = -60x/-60

x = 15/60 ( the minus will cancel out)

x = 1/4

check for your answer  by putting 1/4 where you see x

i.e -5/6(1/4) = -10/3

-5 × 2/3 = -10/3

-10/3 = -10/3......... proved!!

3 0
3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
Answer the question in the picture
nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

Finally,

\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73

4 0
3 years ago
The sum of a number and 4
Klio2033 [76]

Answer:

{4,8,3,7,2,6,1,5,9} the sum of 4

Step-by-step explanation:

4 0
3 years ago
Rosie is investigating factor pairs.
JulsSmile [24]

Answer:

28

Step-by-step explanation:

7 0
3 years ago
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