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3 years ago

What is the solution to the equation x + 4.5 = 20.5?

Mathematics

2 answers:

pishuonlain [190]3 years ago

6 0

Subtract 4.5 from 20.5 and you'll have your answer which is x=16

Vanyuwa [196]3 years ago

5 0

X + 4.5 = 20.5
x + 4.5 - 4.5 = 20.5 - 4.5
x + 0 = 16
x = 16

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I need help. I'm failing math

Alexxandr [17]

Answer:

B i believe

Step-by-step explanation:

6 0

3 years ago

Hey guys ! Can anyone help me with these problems please and thanks

AnnyKZ [126]

m = 3√2√2

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3 0

2 years ago

Set up the equation for the following word problem and solve the equation. Let x be the unknown number. -26 times a number minus

Lelechka [254]

Answer:

Step 1 of 2:
-26x - 5 = x - 56

Step 2 of 2:
17/9 or 1.89

Step-by-step explanation:

1. Putting word statement in algebraic form

Step 1:
Let x be the unknown number ==> x is the unknown variable to be used in the equation and to be solved for

Step 2:
-26 times a number minus 5 ==> -26x - 5

Step 3:
is equal to 56 less than the number ==> = x - 56

Putting it all together:
-26x - 5 = x - 56

2. Solving the equation
-26x - 5 = x - 56

1. Subtract x from both sides:
-26x - 5 - x = x - x -56

-26x -x - 5 = -56

-27x - 5 = -56

2. Add 5 to both sides
-27x - 5 + 5 = -56+ 5

-27x = -51

x = -51/-27 (dividing both sides by -27)

x = 51/27 (negative divide by negative results in positive)

Reduce 51/27 by dividing numerator and denominator by 3

x = (51 ÷ 3)/(27 ÷ 3) = 17/9

= 1.88888.... = 1.89 rounded to two decimal places

7 0

1 year ago

Part 2 - Find the error(s) and solve the problem correctly.

JulijaS [17]

The problem solved correctly as a single logarithm is $log_{a} 2x^{3}/y^{2}$

<h3>Simplifying Logarithm</h3>

From the question, we are to simplify the given logarithm

The given logarithm is

$log_{a} 2x \ + \ 2(log_{a} x -log_{a} y)$

From the subtraction law of logarithm, we have that

$log_{c} a -log_{c} b = log_{c} (a/b)$

Thus,

The error in the solution was instead of multiplying, a was supposed to be divided by b

The correct solution is

$log_{a} 2x \ + \ 2(log_{a} x -log_{a} y)$

$log_{a} 2x \ + \ 2(log_{a} (x/y) )$

$log_{a} 2x \ + \ log_{a} (x/y)^{2}$

$log_{a} 2x \ + \ log_{a} (x^{2}/y^{2})$

Simplifying further

$log_{a} 2x \times (x^{2}/y^{2})$

$log_{a} 2x \times x^{2}/y^{2}$

$log_{a} 2x^{3}/y^{2}$

Hence, the problem solved correctly as a single logarithm is $log_{a} 2x^{3}/y^{2}$

Learn more on Simplifying logarithms here: brainly.com/question/247340

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2 years ago

33 pieces of candy were split among friends. If each

Luba_88 [7]

33-7=26/2=13, so there were 13 friends

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3 years ago