Question

Fractii.(1supra12+1supra24-1supra36):(1supra4+3supra5)×2antregi3supra7​

Answer 1

Answer:

            $\large\boxed{\large\boxed{\dfrac{35}{459}}}$

Explanation:

Fractions:

$\bigg(\dfrac{1}{12}+\dfrac{1}{24}-\dfrac{1}{36}\bigg):\bigg(\dfrac{1}{4}+\dfrac{3}{5}\bigg)\times \dfrac{2}{3}$

1. Solve the first parenthesis:

       $\dfrac{1}{12}+\dfrac{1}{24}-\dfrac{1}{36}=\dfrac{6+3-2}{72}=\dfrac{7}{72}$

2. Solve the second parenthesis:

      $\dfrac{1}{4}+\dfrac{3}{5}=\dfrac{5+12}{20}=\dfrac{17}{20}$

3. Solve the division:

      $\dfrac{7}{72}:\dfrac{17}{20}=\dfrac{7}{72}\times \dfrac{20}{17}=\\ \\ \\ =\dfrac{7\times 20}{72\times 17}=\dfrac{7\times 5}{18\times 17}=\dfrac{35}{306}$

4. Multiply by the last fraction:

        $\dfrac{35}{306}\times \dfrac{2}{3}=\dfrac{35}{153\times 3}=\dfrac{35}{459}$