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Ede4ka [16]
4 years ago
5

Would somebody help me with this problem and a couple more please

Mathematics
1 answer:
vesna_86 [32]4 years ago
6 0
Use the standard equation of a circle with center at (h,k) and radius r:

(x-2)^2 + (y+4) = 3^2

I have helped you several times already with this type of problem.  I'd love to see you demonstrate your growing understanding through sharing some of your own work instead of just asking for answers.
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What's number is 100,000,000 more than 5,438,724,022
Artist 52 [7]

The answer is, as I see it, 5,538,724,022.

Hope this helps

6 0
3 years ago
Read 2 more answers
What will be the value in 5 years?
Stels [109]
The equation for interest also works for depreciation 

the price drops by 11%
or the price of the machine next year would be 89% of this year

the initial price is 60,000
the amount of years is 5
and the percentage of next year is 89

the full equation would be 
60,000(0.89)^5

the price of the machine after five years is 
<span>33504.356694 (not rounded)
the answer you are looking for is C.
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7 0
4 years ago
Read 2 more answers
Solve 5x^2-4x-2=0 by completing the square
konstantin123 [22]

Answer:

Hello

Here's the answer:

2x^2 + 5x + 2 = 0\\&#10;2x^2+4x+x+2=0\\&#10;2x(x+2)+1(x+2)=0\\&#10;(2x+1)(x+2)=0\\&#10;x=-\frac{1}{2} \vee x=-2

x^2-4x+1=0\\&#10;x^2-4x+4-3=0\\&#10;(x-2)^2=3\\&#10;x-2 =\sqrt3 \vee x-2=-\sqrt3\\&#10;x=2+\sqrt3 \vee x=2-\sqrt3

Step-by-step explanation:

5 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
Mt.Everest, the highest elevation in Asia, is 29,028 feet above sea level. The dead sea, the lowest elavation is 1,312 feet belo
mestny [16]

Answer:

30,340 all you gotta do is add the 2 numbers together

7 0
3 years ago
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