What is the equation of a line with a slope of −4 and a point (−2, 5) on the line?
2 answers:
The answer to the question
Answer:
y = -4x + 13
Step-by-step explanation:
m = -4, (-2, 5)
you're going to put this into point-slope form, which is y - y1 = m (x - x1).
y - 5 = -4 (x - (-2))
distribute the -4 (and the two negatives make a positive)
y - 5 = -4x + 8
add five on both sides to get y on its own, on the left, adding 5 to the five cancels out five.
and you get:
y = -4x + 13
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