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miv72 [106K]
3 years ago
8

​What is the equation of a line with a slope of ​ ​ −4 ​ ​ and a point ​ (−2, 5) ​ on the line?

Mathematics
2 answers:
postnew [5]3 years ago
6 0
The answer to the question

n200080 [17]3 years ago
5 0

Answer:

y = -4x + 13

Step-by-step explanation:

m = -4, (-2, 5)

you're going to put this into point-slope form, which is y - y1 = m (x - x1).

y - 5 = -4 (x - (-2))

distribute the -4 (and the two negatives make a positive)

y - 5 = -4x + 8

add five on both sides to get y on its own, on the left, adding 5 to the five cancels out five.

and you get:

y = -4x + 13


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How to integrate sqrt(1+x^3)?
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3 years ago
Which of the following options is a root of the function? f(x) = (3x + 5) (x2 - 6x + 9)2
Alika [10]

Answer:

The roots of the function are x = -5/3 and 3. Select these.

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The roots of the function are the solutions to the function. They are also called the x-intercepts or zeros. To find them, factor the function completely and solve using the zero product property.

f(x) = (3x+5)(x2-6x+9)2 becomes f(x) = (3x+5)(x-3)^2

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