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Aleks04 [339]
3 years ago
3

A student is constructing a triangle with the following dimensions: side length of 10 inches side length of 30 inches Which meas

urements could be the length of the third side? Select all that apply. 19 inches 21 inches 35 inches 45 inches 50 inches
Mathematics
2 answers:
frosja888 [35]3 years ago
3 0

Answer:

21 and 35

Step-by-step explanation:

I took the test and I got it right

have a good day

ella [17]3 years ago
3 0

Answer:

21 and 35 inches

Step-by-step explanation: just did it

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You roll a number cube and flip a coin. Find the probability of rolling a 6 and flipping heads. Write your answer as a fraction
Mandarinka [93]

Answer:1/2 for flipping a coin and 1/6 for rolling a dice

Step-by-step explanation:

There is only two possible sides when flipping the coin one head and another tail so there's is only one way. On a dice there are 6 numbers and only one six so there is only one possibility.

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What is the equation of the line shown in this graph?
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Maths functions <br> please help!
Vlad [161]

Answer:

\textsf{1)} \quad f(x)=-x+3

2)   A = (3, 0)  and C = (-3, 0)

\textsf{3)} \quad g(x)=x^2-9

4)  AC = 6 units and OB = 9 units

Step-by-step explanation:

Given functions:

\begin{cases}f(x)=mx+c\\g(x)=ax^2+b \end{cases}

<h3><u>Part (1)</u></h3>

Given points:

  • H = (-1, 4)
  • T = (4, -1)

As points H and T lie on f(x), substitute the two points into the function to create two equations:

\textsf{Equation 1}: \quad f(-1)=m(-1)+c=4 \implies -m+c=4

\textsf{Equation 2}: \quad f(4)=m(4)+c=-1 \implies 4m+c=-1

Subtract the first equation from the second to eliminate c:

\begin{array}{r l} 4m+c & = -1\\- \quad -m+c & = \phantom{))}4\\\cline{1-2}5m \phantom{))))}}& = -5}\end{aligned}

Therefore m = -1.

Substitute the found value of m and one of the points into the function and solve for c:

\implies f(4)=-1(4)+c=-1

\implies c=-1-(-4)=3

Therefore the equation for function f(x) is:

f(x)=-x+3

<h3><u>Part (2)</u></h3>

Function f(x) crosses the x-axis at point A.  Therefore, f(x) = 0 at point A.

To find the x-value of point A, set f(x) to zero and solve for x:

\implies f(x)=0

\implies -x+3=0

\implies x=3

Therefore, A = (3, 0).

As g(x) = ax² + b, its axis of symmetry is x = 0.

A parabola's axis of symmetry is the midpoint of its x-intercepts.

Therefore, if A = (3, 0) then C = (-3, 0).

<h3><u>Part (3)</u></h3>

Points on function g(x):

  • A = (3, 0)
  • G = (1, -8)

Substitute the points into the given function g(x) to create two equations:

\textsf{Equation 1}: \quad g(3)=a(3)^2+b=0 \implies 9a+b=0

\textsf{Equation 2}: \quad g(1)=a(1)^2+b=-8 \implies a+b=-8

Subtract the second equation from the first to eliminate b:

\begin{array}{r l} 9a+b & =  \phantom{))}0\\- \quad a+b & =-8\\\cline{1-2}8a \phantom{))))}}& =  \phantom{))}8}\end{aligned}

Therefore a = 1.

Substitute the found value of a and one of the points into the function and solve for b:

\implies g(3)=1(3^2)+b=0

\implies 9+b=0\implies b=-9

Therefore the equation for function g(x) is:

g(x)=x^2-9

<h3><u>Part 4</u></h3>

The length AC is the difference between the x-values of points A and C.

\implies x_A-x_C=3-(-3)=6

Point B is the y-intercept of g(x), so when x = 0:

\implies g(0)=(0)^2-9=-9

Therefore, B = (0, -9).

The length OB is the difference between the y-values of the origin and point B.

\implies y_O-y_B=0-(-9)=9

Therefore, AC = 6 units and OB = 9 units

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