This question is incomplete, the complete question is;
An employer has a total of 12 staffs comprising of 7 females and 5 males.
Find the probability that the employer gives vacation hours to 3 males and 3 females if she chooses 6 students from the class at random.
Answer: the required probability is 0.3788
Step-by-step explanation:
Given that;
Total number of staffs = 12
7 females and 5 males
now
Total number of ways to 6 staffs from 12 = ¹²C₆
Number of ways of selecting 3 females and 3 males = ⁷C₃ × ⁵C₃
so,
Probability that the employer gives vacation hours to 3 males and 3 females if she chooses 6 students from the class at random will be;
= ⁷C₃ × ⁵C₃ / ¹²C₆
= ( [7!/(3!×(7-3)!] × [5!/(3!×(5-3)!] ) / [12!/(6!×(12-6)!]
= [35 × 10] / 924
= 350 / 924
= 0.3788
Therefore, the required probability is 0.3788
