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3 years ago

the ratios of the sides of a triangle are 3:2:4. if the shortest side is 26cm, what is the length of the longest side?

Mathematics

1 answer:

zalisa [80]3 years ago

4 0

Answer: 52

Divide 26/2 and you get 13, and then multiply 13 by 4. Think of it as a proportion.

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What is the product of −3/11 and −2/15?

Dafna11 [192]

Multiply -3/11 and -2/15 straight across

-3(-2) = 6
11(15) = 165

6/165 is your product, or 0.036 (rounded)

hope this helps

5 0

3 years ago

Read 2 more answers

The fox population in a certain region has an annual growth rate of 4 percent per year. It is estimated that

Minchanka [31]

Answer:

(a) P(t) = 12100*(1.04^t)

(b) in 2008, estimate of population is 16560 (to the nearest integer)

Step-by-step explanation:

Population in 2000, P(0) = 12100

Growth rate = 4% each year

(a) function model for the t year after 2000 (exponential model)

P(t) = 12100*(1.04^t)

(b) for 2008,

P(2008-2000)

= P(8)

= 12100*(1.04^8)

= 12100 * 1.368569

= 16559.7

= 16560 (nearest integer)

7 0

3 years ago

Make x the subject of the formula x − 3 = q

lakkis [162]

Answer:

x = q + 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define Equation

x - 3 = q

Step 2: Solve for x

Add 3 to both sides: x = q + 3

8 0

2 years ago

Which relation is a function

Anon25 [30]

$\{(\boxed{2};\ 3);\ (1;\ 5);\ (\boxed{2};\ 7)\}-NO\\\\\{(-1;\ 5);\ (-2;\ 6);\ (-3;\ 7)\}-YES\\\\\{(\boxed{11};\ 9);\ (\boxed{11};\ 5);\ (9;\ 3)\}-NO\\\\\{(\boxed{3};\ 8);\ (0;\ 8);\ (\boxed{3};\ -2)\}-NO$

3 0

3 years ago

Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!

Nadya [2.5K]

QUESTION 1

If a function is continuous at $x=a$ , then $\lim_{x \to a}f(x)=f(a)$

Let us find the limit first,

$\lim_{x \to 4} \frac{x-4}{x+5}$

As $x \rightarrow 4$ , $x-4 \rightarrow 0$ , $x+5 \rightarrow 9$ and $f(x) \rightarrow \frac{0}{9}=0$

$\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0$

Let us now find the functional value at $x=4$

$f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0$

Since

$\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4)$ , the function is continuous at $a=4$ .

QUESTION 2

The correct answer is table 2. See attachment.

In this table the values of x approaches zero from both sides.

This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.

The values are also very close to zero unlike those in table 4.

The correct answer is B

QUESTION 3

We want to evaluate;

$\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}$

using the properties of limits.

A direct evaluation gives $\frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}$ .

This indeterminate form suggests that, we simplify the function first.

We factor to obtain,

$\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}$

We cancel common factors to get,

$\lim_{x \to 1} (x+3)^2$

$=(1+3)^2=16$

The correct answer is D

QUESTION 4

We can see from the table that as x approaches $-2$ from both sides, the function approaches $-4$

Hence the limit is $-4$ .

See attachment

The correct answer is option A

3 0

3 years ago