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Romashka-Z-Leto [24]
3 years ago
7

HELP, ASAP! Given that lines b and c are parallel, SELECT ALL THAT APPLY. Which pairs of angles are vertical angles?

Mathematics
1 answer:
mart [117]3 years ago
5 0
2 and three and 4 and 5!
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Multiply each of the following numbers 7.32, and 0.006 by 10, 100, and 1,000. Then explain the pattern you can use to find the p
dangina [55]

7.32

10 = 73.2

100 = 732

1000 = 7320

0.006

10 = 0.06

100 = 0.6

1000 = 6

The decimal place moves to the right depending on how many zeros the number has.

For example, if you had 0.6 multiplied by 100, you would move 2 decimal places to the right because 100 has two zeros.

3 0
3 years ago
Solve #5<br> Is the equation that you use<br> P(t)=P(0)•e^rt ?
Elan Coil [88]
P(t)=(p jk(t)),0 ~ t< 0
5 0
3 years ago
I need urgent help!!
RSB [31]

Answer: I don’t actually know sorry

Step-by-step explanation:

6 0
3 years ago
HELLOOOOOooOOOOOooOOoooOOoo
Viefleur [7K]

Answer:

6. Multiply 2 by 6

7. 71 + 9(8) = 71 + 72 = 143

8. 52 + 3(4) = 12 + 52 = 64

9. 19.25 + 2.75(7) = 19.25 + 19.25 = 38.50

10. 2(0.6)^2 + 4(0.6)(5) = 0.72 + 12 = 12.72

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6 0
3 years ago
Please Help!!
Genrish500 [490]

Given

a\sqrt{x+b}+c=d

we have

\sqrt{x+b}=\dfrac{d-c}{a}

Squaring both sides, we have

x+b=\dfrac{(d-c)^2}{a^2}

And finally

x=\dfrac{(d-c)^2}{a^2}-b

Note that, when we square both sides, we have to assume that

\dfrac{d-c}{a}>0

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

a=1,\ b=0,\ c=2,\ d=6

and you'll have

\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

a=1,\ b=0,\ c=10,\ d=4

and you'll have

\sqrt{x}+10=4 \iff \sqrt{x}=-6

Squaring both sides (and here's the mistake!!) you'd have

x=36

which is not a solution for the equation, if we plug it in we have

\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4

Which is clearly false

7 0
3 years ago
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