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mixas84 [53]
3 years ago
10

Two towns are 540 km apart. If the scale on the map is 2 cm to 50 km, how far apart are the towns on the map?

Mathematics
1 answer:
prohojiy [21]3 years ago
8 0
The answer is 540 / 50, then ans. * 2

which is: 21.6 cm
hope this helps (;
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What is the solution
antoniya [11.8K]

Answer:

3,2 or 1

Step-by-step explanation:

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3 years ago
According to the box-and-whisker plot shown above, what are the following:
Readme [11.4K]

Answer:

  6.  80

  7.  60

  8.  100

  9.  40

  10.  110

Step-by-step explanation:

A box and whisker plot is a visual representation of the 5-number summary of a data set. The features of the plot are, left-to-right, the minimum, first quartile, median, third quartile, maximum.

You are being asked to identify the numerical value associated with each of these features.

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The left whisker extends to the minimum of 40.

The left end of the box identifies the first quartile as 60.

The line in the middle of the box is the median, 80.

The right end of the box identifies the third quartile as 100.

The right whisker extends to the maximum of 110.

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<em>Additional comment</em>

We hope you can rearrange the order of these numbers to suit the order in which the questions ask for them.

4 0
2 years ago
Solve the equation with quadratic formula<br> y^2+3y-10=0
neonofarm [45]

Answer:

y = 2 and y = -5

Step-by-step explanation:

Because the coefficient is not greater than 1, you can simply solve the problem without the quadratic formula.

By using the "x" method, you must figure out what multiplies to give you -10, and adds to give you 3

So, you find your values as 5 and -2. You then set these values equal to zero in terms of Y. As so---- (y+5)=0 and (y-2)=0

Then, you solve out to get your answer! Y is equal to -5 and 2

6 0
2 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
2 years ago
​= <br> The solution set is <br> ​ 1/2(10x+16)-13=-3/5(15x-35)
-BARSIC- [3]

Answer: 13/7 or as a decimal 1.857142857

How did i get the answer:

Step 1: Simplify both sides of the equation.

so 1/2 of 10 is 5, 1/2 of 16 is 8

-3/5 of 15 is -9 and -3/5 of -35 is POSITIVE 21

all together should look like 5x+8+−13=−9x+21

(now we have to combine like terms)

8+ -13= -5

5x -5 = -9x+21

Step 2: Add 9x to both sides

5x + 9x= 14x

14x -5 = 21

Step 3: Add 5 to both sides.

21+5= 26

14x=26

Step 4: Divide both sides by 14.

26/14= 1.85714286 or 13/7

8 0
2 years ago
Read 2 more answers
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