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Kaylis [27]
3 years ago
15

If 3/4 of a cup of yogurt is 80 calories, how many calories are in 1/4 of a cup?​

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
7 0

Answer:

\boxed{\textsf {One fourth cup of yogurt has 26.66 calories. }}

Step-by-step explanation:

Given that ¾ of a cup of yogurt is 80 calories and we need to find the calories in ¼ of a cup . So here we can use unitary method to find the calories.

=> ¾ cup of yogurt has 80 calories

=> 1 cup of yogurt has 80 ÷ ¾ calories .

=> ¼ cup of yogurt has 80 × 4/3 × 1/4 calories = 26.66 calories .

<h3><u>★</u><u> </u><u>Hence </u><u>¼</u><u> </u><u>of </u><u>yogurt</u><u> has</u><u> </u><u>2</u><u>6</u><u>.</u><u>6</u><u>6</u><u> </u><u>calories</u><u>.</u></h3>
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If x+y=10 find the value of y when x = 3
Reptile [31]
Just substitute in the number 3 for x then subtract 3 at both sides and youll have y=7
3 0
3 years ago
Find the side labeled X in the picture, then round to 5 decimal places.
mafiozo [28]

Answer:

\displaystyle x=20.75585

Step-by-step explanation:

<u>Trigonometric Ratios</u>

There are some trigonometric ratios that are defined in a right triangle. The given figure corresponds to a right triangle (with a 90° angle) and two measures are given: An angle of 34° and the length of a side that is opposite to the angle. We are required to find x, the adjacent side of the given angle.

The appropriate relation that we must use to find x is

\displaystyle tan34^o=\frac{14}{x}

Solving for x

\displaystyle x=\frac{14}{tan34^o}

\boxed{\displaystyle x=20.75585}

6 0
3 years ago
Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w
Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1497, \sigma = 322

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1520 - 1497}{322}

Z = 0.07

Z = 0.07 has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

P = 0.4721*0.4721 = 0.2229

22.29% probability that both of them scored above a 1520

8 0
3 years ago
Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c
Allushta [10]

Let the cost of one cup of hot chocolate  be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = 3x+4y=25.50   ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

y=\frac{2x}{3}   .... (2)

Putting the value of y from (2) in (1)

3x+4(\frac{2x}{3})=25.50

=3x+\frac{8x}{3}=25.50

=\frac{9x+8x}{3}=25.50

=17x=76.5

x=4.5

y=\frac{2x}{3}

=\frac{2*4.5}{3}

y =3

Hence each cup of hot chocolate is $4.50

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7 0
3 years ago
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
Ipatiy [6.2K]

Answer:

108

Step-by-step explanation:

Limit as x approaches 9 of x^2 -81/sqrt of x - 3

First substitute x into the expression

= 9²-81/√9 - 3

= 81-81/3-3

= 0/0 (indeterminate)

Apply l'hospital rule

= lim x -> 9 d/dx(x²-81)/√x - 3

= lim x -> 9 2x/1/2√x

Substitute x = 9

= 2(9)/1/2√9

=18/1/(2(3)

=18 × 6/1

= 108

Hence the limit of the function is 108

7 0
3 years ago
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