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2 years ago

How can you use order numbers that are written as fractions, decimals, and percents?

Mathematics

1 answer:

galina1969 [7]2 years ago

7 0

2.5 4/5 8% that is an example of written fractions decimal and percents

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I really need help. What is the answer?

coldgirl [10]

Answer:

4 units

Step-by-step explanation:

3-2=1 unit

7-3=4 units

1*4=4 units

7 0

3 years ago

The lot that Dana is buying for her new one story house is 35 yards by 50 yards. Dana's house plans show that her house will cov

Maslowich

35x50=1,750-1,600=150. We need to find out what 150 is of 1,600.
150/1,600=?/100
1,600 divided by 100=16
do the same for 150
150 divided by 16=9.375
(you can make it whole if you want)
the answer is about 9%

3 0

3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago

Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed

Alekssandra [29.7K]

Answer: The required number of passwords that can be created is 175760.

Step-by-step explanation: Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

$n=9\times17576=175760.$

Thus, the required number of passwords that can be created is 175760.

3 0

3 years ago

Work out m and c for the line: y = 8 − x

vlabodo [156]

The equation is y=mx+c
C=8
M=-1

4 0

2 years ago

Read 2 more answers