What’s the answer to sin 36/85

In a classroom 12 students are wearing glasses, while 6 are not. What percent of the students are wearing glasses? Explainnn

ASHA 777 [7]

Answer:

66,666666666666666666666666666666666667% :))

Step-by-step explanation:

total number of students in 1 class: 12 + 6 = 18 students

percentage of student wearing glasses are:

$\frac{12}{18} \times 100 = 66.666666667\%$

Done :))

4 0

2 years ago

Determine which ordered pair makes the equation true.<br> 2x + y = 11

slavikrds [6]

There is no one ordered pair that makes the equation true, this is a line which has infinitely many ordered pairs that are true...

2x+y=11 subtract 2x from both sides and you have the line in slope intercept form..

y=11-2x

For any real given value of x, you will get one real unique corresponding value for y, resulting in infinitely many unique (x,y) values, points, or ordered pairs, satisfying the given equation.

I assume that you were given "choices" to pick from because of the above reality. So if any of your choices does not satisfy y=11-2x it is not an ordered pair satisfying the equation.

4 0

3 years ago

1) Which pair of angles are congruent?

gavmur [86]

Answer:The eight angles will together form four pairs of corresponding angles. Angles 1 and 5 constitutes one of the pairs. Corresponding angles are congruent. All angles that have the same position with regards to the parallel lines and the transversal are corresponding pairs e.g. 3 + 7, 4 + 8 and 2 + 6.

Step-by-step explanation:

4 0

3 years ago

6th grade math Please help

GaryK [48]

Answer:

17, no remainders.

Step-by-step explanation:

3 0

2 years ago

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 i

stich3 [128]

Complete question :

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 inches. Round answers to the nearest tenth of a percent. a) What percentage of years will have an annual rainfall of less than 43 inches? b) What percentage of years will have an annual rainfall of more than 39 inches? c) What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

Answer:

0.61053

0.66314

0.26647

Step-by-step explanation:

Given that :

Mean (m) = 41.4 inches

Standard deviation (s) = 5.7 inches

a) What percentage of years will have an annual rainfall of less than 43 inches?

P(x < 43)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (43 - 41.4) / 5.7 = 0.2807017

p(Z < 0.2807) = 0.61053 ( Z probability calculator)

b) What percentage of years will have an annual rainfall of more than 39 inches? c)

P(x > 39)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (39 - 41.4) / 5.7 = −0.421052

p(Z > −0.421052) = 0.66314 ( Z probability calculator)

What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

P(x < 38)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (38 - 41.4) / 5.7 = −0.596491

p(Z < −0.596491) = 0.27545 ( Z probability calculator)

P(x < 42)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (42 - 41.4) / 5.7 = 0.1052631

p(Z < 0.1052631) = 0.54192 ( Z probability calculator)

0.54192 - 0.27545 = 0.26647

6 0

3 years ago