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bazaltina [42]
3 years ago
15

Solve for x 3(x+2) + 4(x-5)=10

Mathematics
2 answers:
Fittoniya [83]3 years ago
7 0

Answer:

x= 3.43

Step-by-step explanation:

First, use the distributive property and multiply 3 by x and 3 by 2:

3x + 6

next use the distributive property again and multiply 4 by x and -5:

4x - 20

Combine Like terms: 3x + 6 + 4x - 20

3x + 4x = 7x

6 - 20 = -14

Now Add 14 to both sides: 7x - 14 = 10

10 + 14 = 24

Now divide 7 by both sides: 7x = 24

24 / 7 = 3.428571429 = 3.43

nekit [7.7K]3 years ago
7 0

Answer:

x=24/7 or 3 3/7

Step-by-step explanation:

3(x+2) + 4(x-5)=10   parenthesis first

3x+6+4x-20=10

7x-14=10               addition on both sides

7x-14+14=10+14

7x=24

x=24/7

check the answer:

3(x+2) + 4(x-5)=10

3(24/7+2)+4(24/7-5)=10

72/7+6+96/7-20=10

168/7-14=10

24-14=10

10=10 correct

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From the bottom of the building to the top of the ladder, it is 16 feet.

Step-by-step explanation:

Depending on what grade you are in, you might know the Pythagorean theorem, whose equation is a^2+b^2=C^2 The measurement of the leaning ladder (20ft) is the hypotenuse of the right triangle, the distance from the bottom of the ladder to the building is the leg length (12ft). With this information we know the "c" of the equation, and the "b" or "a" of the equation. If we plug in the number for the letter the equation will look like this:  

12^2+b=20^2. 20 to the second power is 400, and 12 to the second power is 144. You can use the subtraction property of equality and get b^2=256. Use can use a calculator for this part. The square root of 256 is 16, which leaves the equation with b=16

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2 years ago
6r + 7 = 13 + 7r<br> what is r?
lubasha [3.4K]

Answer:

6r + 7 = 13 + 7r

subtract 6r from both sides...

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
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