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Anastasy [175]
3 years ago
7

A recipe calls for 2 teaspoons of orange juice. A can of orange juice is 22 fluid ounces. How many teaspoons of juice are in a c

an
Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0

Answer:

132 teaspoons in a 22 ounce can

Step-by-step explanation:

There are 6 teaspoons in 1 ounce

22 * 6 = 132

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Where is the triangle?

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Having trouble on these type of questions. an explaination would be greatly appreciated
Kazeer [188]

Answer: easy peasy  so your answer would be 4=(6x7)x12 so what you would do is take the first two and dived them your answer you want to dived it with your other numbers

Step-by-step explanation:

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CORRECT ANSWER GETS BRAINLIEST A frequency table of grades has five classes​ (A, B,​ C, D,​ F) with frequencies of ​4,11 ​,15 ​,
ra1l [238]

Answer:

A = 10.5%

B = 28.9%

C = 39.5%

D = 18.4%

F = 2.6%

Step-by-step explanation:

Add all the frequencies together = 38

  • 4/38 × 100 = 10.5%
  • 11/38 × 100 = 28.9%
  • 15/38 × 100 = 39.5%
  • 7/38 × 100 = 18.4%
  • 1/38 × 100 = 2.6%

10.5 + 28.9 + 39.5 + 18.4 + 2.6 = 100%

5 0
3 years ago
Why is 3/2 equal to 3/4
sleet_krkn [62]

Answer:

Step-by-step explanation:

the both eual out to the same equation like how 3/4 equals 0.75 and 3/2 equals 1.5 well if you keep dividing sooner or later they will both be equal at the same number.

7 0
3 years ago
Read 2 more answers
A textbook search committee is considering
lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

  • Repetition is Allowed: such as the lock above. It could be "333".
  • No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

nC_r= \frac{n!}{r! (n-r)!} , where n is the number of things to choose from,  and we choose r of them,  no repetitions,  order matters. Here , n=13 , r=3.

⇒ 13C_3 = \frac{13!}{3!(13-3)!}

⇒ 13C_3 = \frac{13!}{3!(10)!}

⇒ 13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}

⇒ 13C_3 = 13(2)(11)

⇒ 13 C_3 = 286

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0
3 years ago
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