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Temka [501]
3 years ago
10

Please help me smile this problem ASAP

Mathematics
1 answer:
kogti [31]3 years ago
3 0

Answer:

3y^7/ x 3y^5

Photomath

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Answer if you know
xxTIMURxx [149]

Answer:

5157.08m

Step-by-step explanation:

rectangle

100m * 50m = 5000m

Circle

circumference = 2 pi r

2 * 3.14 * 25 = 157.08

157.08 + 5000 = 5157.08m

8 0
3 years ago
Colossus Added to six flags st. Louis in 1986, the Colossus is a giant Ferris wheel. Its diameter is 165 feet, it rotates at a r
NemiM [27]

Given:

D=165 feet and the frequency of the motion is 1.6 revolutions per minute.

Solution:

The radius is half of the diameter.

The radius of the wheel is 82.5 feet.

T=\frac{1}{1.6} \text{ minutes}

As we know: \omega=\frac{2\pi}{T}

Substitute the value of T in the above formula.

\omega=\frac{2\pi}{\frac{1}{1.6}}\\\omega=3.2\pi

If the center of the wheel is at the origin then for t=0 the rest position is -a.

This can be written as:

h(t)=-a\cos(\omega t)\\h(t)=-82.5cos(32.\pi t)

The actual height of the rider from the ground is:

h(t)=\text{ Initial height from bottom}+\text{ radius}-82.5\cos(3.2\pi t)\\h(t)=15+82.5-82.5\cos(3.2\pi t)\\h(t)=97.5-82.5\cos(3.2\pi t)

The required equation is h(t)=97.5-82.5\cos(3.2\pi t).

3 0
3 years ago
Find the value of √(6-3√5)​
Romashka-Z-Leto [24]

Answer:

There is no answer

Step-by-step explanation:

because 3√5=6,7082039232 > 6

So 6-3√5 < 0

But √x always >0

So there is no answer

4 0
3 years ago
Paul and jose are trying to measure the height of a tree. paul is standing 19m from the foot of the tree and measures the angle
Nina [5.8K]
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as x.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
cos(59)= \frac{19}{h}
h= \frac{19}{cos(59)}
h=36.9
Now we can use the law of sines to find the distance x between Paul and Jose:
\frac{sin(43)}{36.9} = \frac{sin(16)}{x}
x= \frac{36.9sin(16)}{sin(43)}
x=14.9

Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
19m+14.9=33.9m

We can conclude that Jose is 33.9m from the base of the tree.

3 0
3 years ago
A cylinder-shaped candle has a diameter of 5 inches and a height of 8 inches.
Arada [10]
V=hpir²
h=8
d=2r
d/2=r
5/2=2.5=r


V=8pi2.5²
V=8pi6.25
V=50pi
aprox pi=3.14

V=50  times 3.14
V=157 in³


157 cubic inches
5 0
4 years ago
Read 2 more answers
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