Answer:
1. C
2. A
Step-by-step explanation:
Given;
A(−4, 0, −8),
B(3, 3, −7),
C(1, 4, 9)
1. y,z plane lies on the that passes x = 0.
xy-plane = (0,y,z)
Therefore, the point closest to the yz is the point with the lowest absolute x (lowest |x|)
For;
A: |x| = |-4| = 4
B: |x| = |3| = 3
C: |x| = |1| = 1
The lowest |x| = 1 which is C
Therefore, the closest point to the yz axis is C
2. xz-plane is the plane passing through y=0.(xz plane = (x,0,z))
For a point to lie on the xz plane, it most be on y=0 (y coordinate must be equal to 0)
So,
For A: (-4,0,-8) = (x,y,z)
For A : y = 0
Therefore, A lies on the xz plane.