[2 sin(x) cos(x)] X [Sin(x)/cos(x)]
<span>The cosines cancel out, as one is in the numerator and one is in the denominator. So you are left with:: </span>
<span>2 sin(x) sin(x) </span>
<span>or: </span>
<span>2 sin(x) [squared]
I hope this helps! </span>
Given:
Two sides of a triangle are 9 and 5.
To find:
The range of possible measures for the third side.
Solution:
In a triangle, the sum of smaller sides must be greater than the largest side.
Let x be the measure of third side.
Case 1: When x is the largest side, then
...(i)
Case 2: When 9 is the largest side, then
...(ii)
Using (i) and (ii), we get
Therefore, the range of possible measures for the third side is .
Answer:
The product of (-5·q·r) × (-2·p·q·r) × p·q is 10·q³·r²·p²
Step-by-step explanation:
The question relates to the rules of multiplication of variables and indices rules, and simplifification of an expression ;
The given expression is (-5·q·r) × (-2·p·q·r) × p·q
Therefore, we have;
(-5·q·r) × (-2·p·q·r) × p·q = (-5) × (-2) × q×q×q × r×r ×p×p = 10 × q³ × r² × p²
10 × q³ × r² × p² = 10·q³·r²·p²
∴ (-5·q·r) × (-2·p·q·r) × p·q = 10 × q³ × r² × p² = 10·q³·r²·p²
(-5·q·r) × (-2·p·q·r) × p·q = 10·q³·r²·p².