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3 years ago

5/11x -11/6 pleaseeeee helpp

Mathematics

2 answers:

maksim [4K]3 years ago

8 0

It is -5/6

I here is the anwer

Makovka662 [10]3 years ago

3 0

X=121/30

Make the base the same and get your answer

Mark brainliest please

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nekit [7.7K]

Answer: $2,160\ ft^3$

Step-by-step explanation:

The first step is to find the ratio of the lengths.

According to the information given in the exercise, one the solids has edges of 12 feet and the other solid has edges of 24 feet.

Therefore, the ratio of the length of the smaller solid to the length of the is the following:

$k=\frac{24\ ft}{12\ ft}\\\\k=2$

Now, the ratio to the volumes of the smaller solid to the other one is the following:

$k^3=2^3=8$

Then, knowing that the volume of the smaller solid is:

$V_s=270\ ft^3$

You get that the volime of the larger solid is:

$V_l=270\ ft^3*8\\\\V_l=2,160\ ft^3$

8 0

3 years ago

Solve for x and y

BigorU [14]

You can use elimination
7x - 3y = 4
-10x + 3y = 2
Add both equations
-3x = 6, x = -2
Plug in -2 for x in one equation
7(-2) - 3y = 4
-14 - 3y = 4
-3y = 18, y = -6
Solution: x = -2, y = -6

4 0

3 years ago

Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to

zepelin [54]

Answer:

(a) $1428

(b) $228

(c) 11 months

Step-by-step explanation:

(a) Total installment price = 119 × 12 = $ 1428

(b) The carrying charges = amount paid - cash price

= 1428 - 1200 = $ 228

(c) No. of needed to save the money = 1200 ÷ 119 = 10.08 ≈ 11 months

7 0

4 years ago

Read 2 more answers

x is less than 1 is the solution to which of the following compound inequalities? A) x is less than 4 AND x is less than 1 B) x

Julli [10]

9514 1404 393

Answer:

A) x is less than 4 AND x is less than 1

Step-by-step explanation:

It's all about understanding the meaning of the English words involved.

A) any member of the solution set must be less than 1 and less than 4. Only numbers less than 1 can satisfy both requirements. (This is the correct choice.)

B) members of the solution set may be less than 1 or may be greater than 3. Numbers less than 1 are part of the solution set, but not all of it.

C) members of the solution set are required to be both greater than 3 and less than 1. There are no such numbers. The solution set is the empty set.

D) members of the solution set may be less than 4 or less than 1. Any number less than 4 will be a member of the solution set.

8 0

3 years ago

The phone lines to an airline reservation system are occupied 40% of the time. Assume that the events that the lines are occupie

nikitadnepr [17]

Answer:

a) $P(X=3)$

And we can use the probability mass function and we got:

$P(X=3) = (10C3) (0.4)^3 (1-0.4)^{10-3} = 0.215$

b) For this case we want this probability:

$P(X \geq 1)$

and the probability that the one call would be not occupied is 1-0.4=0.6

And if we use the complement rule we got:

$P(X \geq 1)= 1-P(X$

$P(X=0) = (10C0) (0.6)^0 (1-0.6)^{10-0} = 0.000105$

$P(X \geq 1)= 1-P(X$

c) $E(X) = np = 10*0.4 = 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

a. What is the probability that for exactly three calls, the lines are occupied?

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.4)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And for this case we want this probability:

$P(X=3)$

And we can use the probability mass function and we got:

$P(X=3) = (10C3) (0.4)^3 (1-0.4)^{10-3} = 0.215$

b. What is the probability that for at least one call, the lines are not occupied?

For this case we want this probability:

$P(X \geq 1)$

and the probability that the one call would be not occupied is 1-0.4=0.6

And if we use the complement rule we got:

$P(X \geq 1)= 1-P(X$

$P(X=0) = (10C0) (0.6)^0 (1-0.6)^{10-0} = 0.000105$

$P(X \geq 1)= 1-P(X$

c. What is the expected number of calls in which the lines are all occupied?

For this case the expected value is given by:

$E(X) = np = 10*0.4 = 4$

8 0

3 years ago