Answer:645 kilometers per hour
Solution.
Let v be the speed of the plane flying east!
Then, the speed of the plane flying west is v+75.
Since the planes are 5460 kilometers apart by 7 pm est,
(7-3)*(v+(v+75))=5460
2v+75=1365,
2v=1290,
v=645
answer: 645
Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
Total = Principal * (1 + rate) ^ years
Total = 1,500 * (1.07) ^ 2
Total = 1,717.35
Answer:
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