Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
4X-4Y>28
X-Y>7 both side divide by 4
Answer:
Sample Response: Break the figure into a parallelogram and a triangle. Find the area of each using the formulas A=bh and A=1/2bh. The sum of the areas is the area of figure.
Step-by-step explanation:
it's a i think, hope this helps
