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3 years ago

50 points help please

Mathematics

2 answers:

weeeeeb [17]3 years ago

8 0

<h3>Answer:</h3>

<em>It would be y=75.</em>

<h3>Step-by-step explanation:</h3>

As if you line up with 20 on the x axis, the scatter of dots passes through at around a range of 60-80. So a reasonable answer would be somewhere within that range. With that, the only available choice within this range is Choice C, or y=75.

yan [13]3 years ago

3 0

Answer:

Step-by-step explanation:

The line of best fit need to start from about 80~ to the end which pass right above the second dot for x=20, so the answer is C.

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A radioactive substance decays according to the formula A=A0e^kt

Sholpan [36]

Without needing fancy formulas, we can conclude that after 10 years, half of the substance will be left. So, we can make our own formula:
amount remaining = 1 / 2^(years/10)
So, after 5 years
amount remaining = 1 / 2^(5/10)
amount remaining = 1 / 2^(.5)
amount remaining = 1 / <span> <span> <span> 1.414213562 </span>
</span></span><span>amount remaining = 0.70711 * 20 grams
</span><span><span><span><span>amount remaining = </span>14.1421356237 grams

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4 0

3 years ago

Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno

Roman55 [17]

Answer:

a) P(X>np+3 $\sqrt{np(1-p)}$ =0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= $\sqrt{0.198}$ ≈ 0.445

a) P(X>np+3 $\sqrt{np(1-p)}$ =P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

$\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}$

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - $\frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}$ - $\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}$

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - $\frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)}$ - $\frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}$

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)= $\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}$ =0.349

P(Y>1)=1-0.349=0.651

3 0

3 years ago

Use synthetic division to solve (x4 – 1) ÷ (x – 1). What is the quotient?

postnew [5]

Answer:

Simplify, x(3) + x(2) + x + 1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please please, please

Masja [62]

The production of health drink cans at a warehouse can be represented by the equation below, where x represents the hours of production, and y the total supply of items in the warehouse, in hundreds.

Which of the following graphs represents this situation?

the equation is y= 3/5x+2

I drew the graph.

3/5 is the slope, and 2 is the y-intercept. So you start at (0,2), and go up 3 units, then right 5.

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hope it helps