Answer:
Step-by-step explanation:
Angle A:
Because quadrilateral ABCD is cyclic, angles A and C are supplementary. This means angle A = 180 - 101 = 79 degrees
Angle B: same kind of logic as A
so
x = 6 over 5
mark me brainliest if u have any doubt ask me
B. is the correct answer
I suppose you're trying to make a triangle of some sort on a plane! So, in this case, yes the three points would reside all on the same plane. Making all three of them collinear.
