D.
-5(-1) + 2(2) = 5 + 4 = 9
-3 + 10 = 7
Answer:
8
Step-by-step explanation:
hope it will help good luck
Answer:

Step-by-step explanation:
1. Approach,
For this problem, the format of a line that will be used is, slope-intercept form;

Where (
) is the slope of the line, also known as the change in the line and
is the y-intercept, or where the graph of the line intersects the y-axis. Since, in this problem, the slope of the line is given, all one has to do is substitute in a point on the given line and solve.
2. Finding the equation,
In this problem, the slope of the line is given. Therefore, to solve this problem, all one has to do is substitute in a point on the given line and solve.

Substitute in the slope,

Substitute in the point,

Simplify,

Inverse operations,

3. Putting it all together,
Now, that one has y-intercept, (
); use the given slope and the formula
, substitute in all the information.

Answer with Step-by-step explanation:
We are given that

Where t corresponds to the year 2000=0
a.
Substitute the values


b.In 2004
t=4


c.In 2013
t=13

Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588