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3 years ago

Use proportional reasoning to determine the value of a in the proportion shown below.

2 answers:

8 0

We have
<span>3/5=(a+5)/25
3/5=(5/5)*(3/5)=15/25
therefore
15/25=</span>(a+5)/25<span>
15=a+5------------------------ > a=10

the answer is the option </span>a = 10

kicyunya [14]3 years ago

4 0

Answer:

A=10

Step-by-step explanation:

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blsea [12.9K]

Answer:

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Step-by-step explanation:

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3 years ago

The midpoint of segment XY is (6, -3). The coordinates of one endpoint are X(-1, 8). Find the coordinates of endpoint Y.

Snezhnost [94]

Answer:

The answer to your question is: Y = (13, -14)

Step-by-step explanation:

Data

midpoint = mp = (6, -3)

one endpoint = X = (-1, 8)

second endpoint = Y = (x, y)

Formula

Xmp = (x1 + x2) / 2

Ymp = (y1 + y2) / 2

Process

x2 = 2xmp - x1

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3 years ago

3x10 to the second power

aalyn [17]

Answer: 300

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3 years ago

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f left parenthesis x right parenthesis equals StartFraction 16 x squared Over x Superscript 4 Baseline plus 64 EndFractionf(x)=1

Jlenok [28]

Answer:

a) Yes

b) (2,0.8)

c) $(2\sqrt2,1), (-2\sqrt2,1)$

d) $x \in (-\infty,\infty)$

e) (0,0)

f) (0,0)

Step-by-step explanation:

We are given the following function in the question:

$f(x) = \displaystyle\frac{16x^2}{x^4 + 64}$

a) We have to check whether given point lies on the function or not.

$(-2\sqrt2,1)\\\\f(-2\sqrt2) = \displaystyle\frac{16(-2\sqrt2)^2}{(-2\sqrt2)^4 + 64} = \frac{128}{128} = 1$

b) Find value of f(x) at x = 2

$f(2) = \displaystyle\frac{16(2)^2}{(2)^4 + 64} =\frac{64}{80}= 0.8$

Thus, (2,0.8) lies on the graph of given function.

c) We have to find the value of x, when f(x) = 1

$1 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\x^4 -16x^2 + 64 = 0\\(x^2-8)^2 = 0\\x^2 - 8 = 0\\x = \pm 2\sqrt2$

$(2\sqrt2,1), (-2\sqrt2,1)$ lies on he graph of function.

d) Domain is the collection of all values of x for which the function is defined.

$x \in (-\infty,\infty)$

e) x-intercepts

This is the value of x such that the function is zero.

$0 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\16x^2 = 0\\x = 0$

f) y-intercept

It is the value of function when x is zero.

$f(0) = \displaystyle\frac{16(0)^2}{(0)^4 + 64} = 0$

The function passes trough origin.

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Answer:

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3 years ago

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