1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2
Answer:
-1,0,2,-2,0 in that order
Step-by-step explanation:
Answer:
3.14159265359
Step-by-step explanation:
Answer:
Option (A)
Step-by-step explanation:
Te given equation is,
-qx + p = r
Toe find the value of x,
By subtracting p from both the sides of the equation.
-qx + p - q = r - q
-qx = r - q
By dividing the whole equation by (-q),
x = 
x = 
Therefore, Option (A) will be the answer.
