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3 years ago

5

How to solve Y=1/2X+2

1 answer:

Oxana [17]3 years ago

8 0

<span>x-intercept is when y = 0

0 = -1/2x - 2
1/2x = -2
x = -4
x-intercept = (-4,0)

y-intercept is when x = 0

y = -1/2(0) - 2
y = -2
y-intercept = (0, -2)
(note that in the form y = mx+b, b is the y-intercept, so in y = -1/2x - 2, -2 is the y-intercept)

Now to graph, simply plot these two points (-4, 0) and (0, -2) and draw a line between them.

Best of luck!</span>

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2(3 + 4x) = 8x + 6<br> How Many solutions?

Mrrafil [7]

Answer:

Infinite number of solutions

Step-by-step explanation:

$2(3 + 4x) = 8x + 6\\6 + 8x = 8x+6\\8x-8x=6-6\\0=0$

For any value of x, both equations are equal to each other because both sides are identical

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2 years ago

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Suppose that the mean score of a class of 32 students was 74. the 19 male students in the class had a mean score of 70. what was

andrew-mc [135]

Mean = sum of values / number of values
74 = x/32
2368 = x

70 = y/19
1330 = y

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2 years ago

John is selling tickets to an event. Attendees can either buy a general admission ticket, x,

Masteriza [31]

John sold 18 general admission tickets and 11 VIP tickets.

Step-by-step explanation:

Given,

Cost of each general admission = $50

Cost of each VIP ticket = $55

Total tickets sold = 29

Total revenue generated = $1505

Let,

x represent the number of general admission tickets sold

y represent the number of VIP tickets.

x+y=29 Eqn 1

50x+55y=1505 Eqn 2

Multiplying Eqn 1 by 50

$50(x+y=29)\\50x+50y=1450\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(50x+55y)-(50x+50y)=1505-1450\\50x+55y-50x-50y=55\\5y=55$

Dividing both sides by 5

$\frac{5y}{5}=\frac{55}{5}\\y=11$

Putting y=11 in Eqn 1

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John sold 18 general admission tickets and 11 VIP tickets.

Keywords: linear equation, elimination method

Learn more about elimination method at:

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2 years ago

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Step-by-step explanation:

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2 years ago

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Find the distance between each pair of points.<br> 3) (6, -2), (8, -3)<br> 4) (7,-8), (-8, 2)

castortr0y [4]

Answer:

3) $\sqrt{5}$

4) $5\sqrt{13}$

Step-by-step explanation:

distance between two points:

$d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}$

we have:

3) (6, -2), (8, -3)

$x_{1} = 6$

$y_{1} =-2$

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$y_{2} =-3$

so we have:

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$y_{1} =-8$

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2 years ago