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olga_2 [115]
3 years ago
7

A square is made up of an L-shaped region and three transformations of the region. If the perimeter of the square is 40 units, w

hat is the perimeter of each L-shaped region?
Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

20 units

Step-by-step explanation:

This implies that the square can be divided into four equal L-shaped regions. These regions with respect to transformation forms a square.

Perimeter of the square is 40 units. Since a square has equal length of sides, thus each side of the square is 10 units.

Thus, each L-shape region has dimensions; 8 units, 5 units, 5 units and 2 units.

Perimeter of each L-shape region = the addition of the length of each side of the shape

Perimeter of each L-shape region = 8 + 5 + 5 + 2

                                                         = 20 units

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Nutka1998 [239]

Let i = sqrt(-1) which is the conventional notation to set up an imaginary number

The idea is to break up the radicand, aka stuff under the square root, to simplify

sqrt(-8) = sqrt(-1*4*2)

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sqrt(-8) = i*2*sqrt(2)

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5 0
3 years ago
Whats the area of a circle with a circumference of 31.4unit
marin [14]

Answer:

78.54

Step-by-step explanation:

first you have to divided 31.4 by 3.14 to get your diameter so you can get your radius. 31.4 divided by 3.14 equals 10 and 10 divided by 2 equals 5 which is you radius.  The formula for area for a circle is πr². 5 squared is 25 and 3.14 times 25 equals 78 .54 which is your answer.

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Read 2 more answers
5x-3x(26x-7x-28x) systems of equation
labwork [276]

Simplifying
5x + 2(8x + -9) = 3(x + 4) + -5(2x + 7)

Reorder the terms:
5x + 2(-9 + 8x) = 3(x + 4) + -5(2x + 7)
5x + (-9 * 2 + 8x * 2) = 3(x + 4) + -5(2x + 7)
5x + (-18 + 16x) = 3(x + 4) + -5(2x + 7)

Reorder the terms:
-18 + 5x + 16x = 3(x + 4) + -5(2x + 7)

Combine like terms: 5x + 16x = 21x
-18 + 21x = 3(x + 4) + -5(2x + 7)

Reorder the terms:
-18 + 21x = 3(4 + x) + -5(2x + 7)
-18 + 21x = (4 * 3 + x * 3) + -5(2x + 7)
-18 + 21x = (12 + 3x) + -5(2x + 7)

Reorder the terms:
-18 + 21x = 12 + 3x + -5(7 + 2x)
-18 + 21x = 12 + 3x + (7 * -5 + 2x * -5)
-18 + 21x = 12 + 3x + (-35 + -10x)

Reorder the terms:
-18 + 21x = 12 + -35 + 3x + -10x

Combine like terms: 12 + -35 = -23
-18 + 21x = -23 + 3x + -10x

Combine like terms: 3x + -10x = -7x
-18 + 21x = -23 + -7x

Solving
-18 + 21x = -23 + -7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7x' to each side of the equation.
-18 + 21x + 7x = -23 + -7x + 7x

Combine like terms: 21x + 7x = 28x
-18 + 28x = -23 + -7x + 7x

Combine like terms: -7x + 7x = 0
-18 + 28x = -23 + 0
-18 + 28x = -23

Add '18' to each side of the equation.
-18 + 18 + 28x = -23 + 18

Combine like terms: -18 + 18 = 0
0 + 28x = -23 + 18
28x = -23 + 18

Combine like terms: -23 + 18 = -5
28x = -5

Divide each side by '28'.
x = -0.1785714286

Simplifying
x = -0.1785714286
3 0
3 years ago
Complete parts a through f below to find nonnegative numbers x and y that satisfy the given requirements. Give the optimum value
MArishka [77]

Answer:

  • y = 81-x
  • the domain of P(x) is [0, 81]
  • P is maximized at (x, y) = (54, 27)

Step-by-step explanation:

<u>Given</u>

  • x plus y equals 81
  • x and y are non-negative

<u>Find</u>

  • P equals x squared y is maximized

<u>Solution</u>

a. Solve x plus y equals 81 for y.

  y equals 81 minus x

__

b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.

  P equals x squared left parenthesis 81 minus x right parenthesis

__

c. Find the domain of the function P found in part b.

  left bracket 0 comma 81 right bracket

__

d. Find dP/dx. Solve the equation dP/dx = 0.

  P = 81x² -x³

  dP/dx = 162x -3x² = 3x(54 -x) = 0

The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...

  P is maximized at (x, y) = (54, 27).

7 0
3 years ago
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