Answer:
the probability of an adult getting a NEG result and truly having tuberculosis is 0.0127
Step-by-step explanation:
S = the adult really has tuberculosis.
S' = complement of S = the adult does not has tuberculosis.
POS = the test gives a positive result
P(S)= 0.05
P(POS | S)=0.746
P(NEG | S')= 0.7653
this is an intersection because the "and" word
P(NEG ∩ S) = P(NEG| S)*P(S)=(1-P(POS | S))*P(S)=(1-0.746)*0.05=0.0127
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Answer: -4/7 count 4 down and 7 across
Explanation:
I hope this helped!
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- Zack Slocum
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the correct answer to your question is 10
<span>-16 - w, when w = -23
-16 - (-43) = 27</span>
Solution :
The null and alternative hypothesis is given by
Assume that the level of significance, α = 0.05
The t-test statistics is, t = 1.484
Degree of freedom :
df = n - 1
= 14 - 1
= 13
The P-value is given by
P-value = 2P (T>|t|)
= 2P(T>|1.484|)
= 2P(T>1.484)
= 2(=T.DIST.RT(1.484,13))
= 0.05
