Answer: excused by Delta's failure to pay.
Explanation:
Delta Construction Corporation hires Eagle Electrical Company, as a subcontractor, to wire its new office building. After the completion of the work, Eagles is owed more than $50000.
Eagle's suspension of work is most likely due to the excuse by Delta's failure to pay. Delta has a right to pay up the money owed to Eagle. Lack of payment can lead to court cases.
Answer: coaching Joe rather than helping him.
Explanation:
Based on the scenario in the question, Becca's approach to getting Joe up to speed indicates that she is coaching rather Joe than helping him.
A coach is someone who guides someone and makes them better and believe in themselves. Since Becca has provided Joe with guidance by offering advice, encouragement, and instructions, this shows that Becca has been coaching him.
Answer:
The amount of Current liabilities is $7,710
Explanation:
The amount of current liabilities on the classified balance sheet is seen below;
Constable Corp.
Balance sheet as at December 31, year 1.
Current liabilities
Accounts payable $4,540
Wages payable $3,170
Total $7,710
Answer:
$4,5243.63
Explanation:
Data provided in the question:
Future value = $250,000
Interest rate = 5% = 0.05
Time = 5 years
Now,
Future value = ![C\times\left[ \frac{(1+i)^{n}-1}{i} \right]](https://tex.z-dn.net/?f=C%5Ctimes%5Cleft%5B%20%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%20%5Cright%5D)
here,
C = Regular deposit amount
i = Interest rate per period
n = number of periods
Future value = ![C\times\left[ \frac{(1+i)^{n}-1}{i} \right]](https://tex.z-dn.net/?f=C%5Ctimes%5Cleft%5B%20%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%20%5Cright%5D)
or
$250,000 = ![C\times\left[ \frac{(1+0.05)^{ 5}-1}{ 0.05} \right]](https://tex.z-dn.net/?f=C%5Ctimes%5Cleft%5B%20%5Cfrac%7B%281%2B0.05%29%5E%7B%205%7D-1%7D%7B%200.05%7D%20%5Cright%5D)
$250,000 = ![C\times\left[ \frac{ 1.05^{ 5}-1}{ 0.05} \right]](https://tex.z-dn.net/?f=C%5Ctimes%5Cleft%5B%20%5Cfrac%7B%201.05%5E%7B%205%7D-1%7D%7B%200.05%7D%20%5Cright%5D)
$250,000 = ![C\times\left[ \frac{ 1.276282 - 1}{ 0.05} \right]](https://tex.z-dn.net/?f=C%5Ctimes%5Cleft%5B%20%5Cfrac%7B%201.276282%20-%201%7D%7B%200.05%7D%20%5Cright%5D)
$250,000 = C × 5.52564
or
C = 
C = $4,5243.63
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate,
= 6 boats per hour.
Service rate,
= 10 boats per hour.
Probability of zero boats in the system,
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
=
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.