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MAVERICK [17]
2 years ago
8

Need help ASAP !!!! Solve for y

Mathematics
1 answer:
GarryVolchara [31]2 years ago
8 0

Answer:

y=8.94

Step-by-step explanation:

use the formula: a^2+b^2=c^2

64+y^2=144

y=\sqrt{80}

or y=8.94

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HELP PLEASSEEEE I NEED TO FIND THE MISSING SIDE HYPOTENUSE
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Answer:

B. 6.5

Step-by-step explanation:

You can use the 5 against the unknown number and  add a few more moves which makes it 6.5.. It's easier in my head man.

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3 years ago
You and a friend each have a collection of tokens. Initially, for every 8 tokens you had, your friend had 3. After you give half
vlada-n [284]
If your friend now has 18 that means you had 48, as mentioned above, you had given half of your tokens, half of 48 is 24. =24
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3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
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likoan [24]

Answer:

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3 years ago
Expand to write an equivalent expression: -1/4(-8x+12y)
lapo4ka [179]

Answer:

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Step-by-step explanation:

Distribute -1/4 to all the terms in the brackets.

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2x - 3y

7 0
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