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Fiesta28 [93]
3 years ago
8

What value of c makes the polynomial below a perfect square? 4x2 + 12x + c?

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0
Blessesmom1 is correct C would equal 9
Tema [17]3 years ago
6 0
This is what we know:4x^2 + 12x + c = (2x + k)^2
<span> 4x^2 + 12x + c = 4x^2 + 2kx + 2kx + k^2 
c=9
</span>
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Help please................
Alona [7]
Hey you're using Apex xD

Answer is D. 

Here's an example 

6= 3x2
Just divide. 6/2 = 3 <span />
8 0
3 years ago
PLS HELP ME 16 and 17
mixer [17]
The distance is 36 from 16 there u go
4 0
3 years ago
Solve for w<br><br> -w + 181 = 128<br><br> w = ____
JulsSmile [24]
W = -53
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4 0
2 years ago
Uranus moves in an elliptical orbit with the sun at one of the foci. The length of the half of the major axis is 2,876,769,540 k
Alina [70]

Answer:

The minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

Step-by-step explanation:

Consider the provided information.

The length of the half of the major axis is 2,876,769,540 kilometers, and the eccentricity is 0.0444.

The eccentricity (e) of an ellipse is the ratio of the distance from the center to the foci (c) and the distance from the center to the vertices (a).

e=\frac{c}{a}

Substitute a = 2,876,769,540 and e = 0.0444 in above formula and solve for c.

0.0444=\frac{c}{2,876,769,540 }

c=127728567.576

Minimum distance of Uranus from the sun is:

a-c=2,876,769,540-127728567.576\\a-c=2749040972.424\approx2749040972

Hence, the minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

6 0
3 years ago
Help me please. Thank you in advance ​
Dmitriy789 [7]
Your answer is going to be roughly 9.3327
3 0
2 years ago
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