Evaluate |-6| + 3|4| + |-5| - 0 × 6.
2 answers:
Hey there!
<h2>|-6| +3|4| + |-5| - 0(6) </h2><h2>6+ 3(4) + |-5| - 0(6) </h2><h2>3(4) = 12 </h2><h2>6+12+|-5| -0(6) </h2><h2>6 + 12 = 18 </h2><h2>18 + |-5| - 0(6) </h2><h2>18 + 5 - 0(6) </h2><h2>18 + 5 = 23 </h2><h2>23 - 0(6) </h2><h2>0(6) = 0 </h2><h2>23 - 0 = 23 </h2><h2>Answer: 23 (Option C) </h2><h2>Good luck on your assignment and enjoy your day! </h2><h2>~You might be interested in
Answer:
A trapezoid ABCD is show below,
AB || CD
AC and BD are diagonals intersecting at P.
(a)
In Δ ABC and ABD,
Area of triangle ABC = Area of triangle ABD
Because,
Area of triangle ABC = 1/2 × Base × Height
Base = AB
Height = h, which is same for both the triangle that's why,
Area of triangle ABC = Area of triangle ABD
(b)
As we know that,
Area of triangle ABC = Area of triangle ABD
On subtracting the area of triangle ABP from both the triangles, we get
Area of triangle ABC - area of triangle ABP = Area of triangle ABD - area of triangle ABP
⇒ area of triangle BCP = area of triangle DAP
Hence, triangles BCP and DAP have the same area.
(c)
In triangle ABP and CDP,
∠ABP = ∠CDP (opposite interior angles are equal between two parallel lines)
∠APB = ∠CPD (opposite angles are equal)
∠BAP = ∠DCP (opposite interior angles are equal between two parallel lines)
Therefore,
By AAA similarity
Triangles ABP and CDP are similar.
(d)
In triangle BCP and DAP,
Only ∠BCP = ∠APD (opposite angles are equal).
Therefore,
Triangles BCP and DAP need not be similar.
