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3 years ago

20 points, asap please!

Mathematics

2 answers:

labwork [276]3 years ago

8 0

F(x) is -4, g(x) is 4, h(x) is 1.

For the f(x), it is in vertex form, which is a(x-h)^2+k. The a.o.s. Is the opposite of h, therefore, it’s -4.

For the g(x), it is in standard form, which is ax^2 + bx + c, you can use the formula -b/2a to find the a.o.s. So, -(-16)/2(2) is 4.

For the h(x), just look at the graph and find where the middle of the parabola is. When you go to 1 on the x-axis and draw a vertical line, it cuts the parabola into half. 1 is the a.o.s.

Note: f(x), g(x), and h(x) can also be 0 or y.

devlian [24]3 years ago

4 0

H(x)=-3,1 I think hope this helps

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Lesechka [4]

Answer:

v = -3

Step-by-step explanation:

1) Expand.

3v + 4v - 8 = -29

2) Simplify 3v + 4v - 8 to 7v - 8.

7v - 8 = -29

3) Add 8 to both sides.

7v = -29 + 8

4) Simplify -29 + 8 to -21.

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5) Divide both sides by 7.

v = -21/7

6) Simplify 21/7 to 3.

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3 years ago

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natta225 [31]

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Step-by-step explanation: Hope this helps :)

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DedPeter [7]

Answer:

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

Where,

$\bar x_1$ = sample meaan of population 1

$\bar x_2$ = sample mean of population 2

$n_1$ = sample size of population 1

$n_2$ = sample size of population 2

Therefore, this is the test

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

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