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jeka94
4 years ago
15

14x-y=42 what is the slope

Mathematics
1 answer:
igomit [66]4 years ago
8 0

Answer:

14


Step-by-step explanation:

14x-y=42

14x=42+y

y=14x-42

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PLEASE HELP ME! ASAP
Leokris [45]

Answer:

I think the answer is 111 degrees

Step-by-step explanation:

you add 19 plus 50 and you get 69

every triangle equals 180 degrees

so then you subtract 180 to 69 and get 111

8 0
3 years ago
The half-life is a substance is 375 years. If 70 grams is present now, how much will be present in 500 years?
Lynna [10]

Answer:

27.76 grams will be present in 500 years

Step-by-step explanation:

The given formula is A=A_{o}e^{kt} , where A is the value of the substance in t years, and A_{o} is the initial value

∵ The half-life is a substance is 375 years

- Substitute A by \frac{1}{2}A_{o} and t by 375 to find the value of k

∴ \frac{1}{2}A_{o}=A_{o}e^{375k}

- Divide both sides by A_{o}

∴ \frac{1}{2}=e^{375k}

- Insert ㏑ in both sides

∴ ㏑( \frac{1}{2} ) = ㏑ ( e^{375k} )

- Remember ㏑ ( e^{n} ) = n

∵ ㏑ ( e^{375k} ) = 375 k

∴ ㏑( \frac{1}{2} ) = 375 k

- Divide both sides by 375

∴ k ≈ -0.00185

∴  A=A_{o}e^{-0.00185t}

∵ 70 grams is present now

- That means the initial value is 70 grams

∴ A_{o} = 70

∵ The time is 500 years

∴ t = 500

- Substitute the values of A_{o} and t in the formula

∵ A=70e^{-0.00185(500)}

∴ A = 27.76

∴ 27.76 grams will be present in 500 years

3 0
3 years ago
(4a2 - 3b2)(16a4 +12a2b2 + 9b4)
Lynna [10]

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Step-by-step explanation:

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3 years ago
the aquarium has 30 times as many fish in one tank as jacob had. the aquarium has 90 fish. how many fish does jacob have
Stolb23 [73]
Jacob has three fish.
8 0
3 years ago
A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inche
Mademuasel [1]

Answer:

The correct option is

A.  \ \dfrac{1}{c} \times \left | x - 5 \right | = 0.3

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is \dfrac{1}{c} \times \left | x - 5 \right | = 0.3 or \left | x - 5 \right | = 0.3 \times c which gives the correct option as A

8 0
4 years ago
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