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TiliK225 [7]
3 years ago
5

S.P. + vat of TV. = 4950 Vat% - 10% S.P of TV, with out vat = ?

Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

S.P without V.A.T = S.P + V.A.T% of S.P

Step-by-step explanation:

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What is 45 divided by 70?
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0.6428571429

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9/14

this is the answer

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A certain 90-mile trip took 2 hours. Exactly 1/3 of the distance traveled was by rail and this part of the trip took 1/5 of the
antiseptic1488 [7]

The average rate, in miles per hour, of the rail portion of the trip is; D: 75

<h3>How to calculate the average speed?</h3>

Since exactly 1/3 of the distance travelled was by rail, then we can say that;

(1/3) * (90) = 30 miles

We are told that part of the trip took 1/5 of the travel time. Thus;

Time it takes to travel that distance is:

(1/5) * (2) = 2/5 of an hour

Average rate is;

30/(2/5) = 150/2 = 75 mph

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2 years ago
Q - 8 as a verbal expression
sertanlavr [38]

Answer:

Step-by-step explanation:

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8 0
3 years ago
What is the proof by reduction to absurdity?​
Naddika [18.5K]

Answer:

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5 0
3 years ago
Anne is running on a trail at an average speed of 6 miles per hour beginning at mile marker 4. John is running on the trail at t
Sphinxa [80]

Answer:

John is running faster.

Step-by-step explanation:

Given that:

Average Speed of Anne = 6 miles per hour

Speed of John can be represented in the table below:

\begin{center}\begin{tabular}{ c c}Time (hours) x & Mile Marker y \\ 0 & 1  \\  0.5 & 4.5  \\   1 & 8  \\ 1.5 & 11.5  \\\end{tabular}\end{center}

To find:

Who is running faster of the both i.e. Anne and John?

Solution:

Here, to find the faster runner we can compare the average speed of both the runners.

We are given that, average speed of Anne = 6 miles per hour

We will have to calculate the average speed of John to find the faster runner.

<em>Average speed</em> can be calculated by dividing the total distance traveled with the total time taken.

Total distance traveled by John = 11.5 - 1 = 10.5 miles

Total time taken by John = 1.5 hours

Average speed of John = \frac{10.5}{1.5} = 7\ miles/hr

Clearly Average speed of John is greater than that of Anne's.

Therefore, <em>John runs faster</em>.

6 0
3 years ago
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