Answer:
![\boxed{\rm \: Volume_{(Drum)} = 5024 \: in {}^{3} }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Crm%20%5C%3A%20Volume_%7B%28Drum%29%7D%20%3D%205024%20%5C%3A%20in%20%7B%7D%5E%7B3%7D%20%7D)
Step-by-step explanation:
Given :
- Diameter of a drum = 20 inches
- Deep ( height ) of the drum = 16 inches
- π = 3.14
To Find:
The volume of the drum.
Solution:
We all know that drum is cylindrical.So we'll use the formulae of the volume of cylinder,to find its volume.
![\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%7Br%7D%20%7B%7D%5E%7B2%7D%20h%7D)
Where,
- r = radius
- h = height (deep)
- π = 3.14
The value of radius ain't given,but the diameter is given.We can use the formulae of radius.
![\rm \: Radius = D/2](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Radius%20%3D%20D%2F2)
Substitute the value of diameter:
![\rm \: Radius = \cfrac{20}{2} = 10](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Radius%20%3D%20%20%5Ccfrac%7B20%7D%7B2%7D%20%20%3D%2010)
Hence,the radius is 10.
So we could now use the formulae of the volume of cylinder:
![\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%7Br%7D%20%7B%7D%5E%7B2%7D%20h)
- π = 3.14
- r =10 in
- h = 16 in
<em>[Firstly bring the answer in terms of π then plug π = 3.14 and then simplify.]</em>
![\rm \: Volume_{(Drum)} = \pi(10) {}^{2} (16)](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Drum%29%7D%20%3D%20%5Cpi%2810%29%20%7B%7D%5E%7B2%7D%20%2816%29)
![\rm \: Volume_{(Drum)} =\pi100(16)](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Drum%29%7D%20%3D%5Cpi100%2816%29)
![\rm \: Volume_{(Drum)} = 1600\pi](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Drum%29%7D%20%3D%201600%5Cpi)
![\rm \: Volume_{(Drum)} = 1600 \times 3.14](https://tex.z-dn.net/?f=%20%5Crm%20%5C%3A%20Volume_%7B%28Drum%29%7D%20%3D%201600%20%5Ctimes%203.14)
![\boxed{\rm \: Volume_{(Cylinder)} = 5024 \: in {}^{3}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Crm%20%5C%3A%20Volume_%7B%28Cylinder%29%7D%20%3D%205024%20%5C%3A%20in%20%7B%7D%5E%7B3%7D%7D%20)
<u>Hence, we can conclude that:</u>
The volume of this drum is 5024 in^3.
Answer:
A)
Step-by-step explanation:
The starting point to solve this, is to gather the concept of what a Rhombus is, an Equilateral Parallelogram, so let's examine the following options
A. All sides are of equal length. True
Considering the definition hence all sides have the same length.
B. <em>The Diagonals are of equal length</em> False. Since there is a bigger diagonal than the second Diagonal, we cannot assure they're of equal lengths.
Check the picture out below
C. <em>The opposite sides are of equal length and the diagonals are of equal length </em>False. Since those diagonals are different we cannot agree with the second part
D. <em>The opposite sides are parallel and the diagonals are of equal length</em> False Different length for each diagonal.
Answer:
7) 7.8*10^0
8) 3.2
*
10
^-7
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Answer:
1x + 4y = 4 ⇒ 6x + 24y = 24
6x - 8y = 0 ⇒ 6x - 8y = 0
32y = 24
32 32
y = 3/4
x + 4(3/4) = 4
x + 3 = 4
-3 -3
x = 1
(x, y) = (1, 3/4)
Step-by-step explanation:
up there :D
Either BOD or AOD
Hope this helps c: