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Veronika [31]
3 years ago
11

As regards the web browser Safari, which of the statements is correct? Group of answer choices It has the highest market share o

f 45%. It is the dominant browser for Macintosh computers. It was initially bundled with the OS of Microsoft to gain an early lead in the "browser wars." It is also known by the name of Opera in mobile phones.
Computers and Technology
1 answer:
SashulF [63]3 years ago
4 0

Answer:

It is the dominant browser for Macintosh computers.

Explanation:

Safari is undoubtedly dominant browser in Apple products. So, it is the dominant browser for Macintosh computers.

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Write a SELECT statement that returns one row for each customer that has orders with these columns:
d1i1m1o1n [39]

Answer:

SELECT email_address,

SUM(item_price * Quantity) AS item_price_total,

SUM(discount_amount * Quantity) AS discount_amount_total

FROM Customers c

JOIN Orders o ON c.CustomerID = o.CustomerID

JOIN Order_Items oi ON o.OrderID = oi.OrderID

GROUP BY email_address

ORDER BY item_price_total DESC

Explanation:

In this SQL statement the SELECT statement selects the following columns:

email_address

item_price

Quantity

discount_amount

There are two tables Customers and Order_Items

SUM aggregate function is used to add the values of the product of the columns discount_amount and Quantity. It is also used to get the sum of the product of two columns discount_amount and Quantity.

A new temporary column named item_price_total is used to name the sum of the product of two columns discount_amount and Quantity using AS which is ALIAS and it is used to give a name to some columns or a table.

Similarly discount_amount_total name is given to the column which calculate the sum of the product of two columns i.e. discount_amount and Quantity.

JOIN is used here to join the columns from the tables Order_items and Customers.

GROUP BY is used to group the result of rows and is used with functions like SUM. Here the rows are grouped by the email address.

ORDER BY is used to order the result. Here the result is ordered by item_price_total in descending  order.

This SELECT statement can also be written as following:

SELECT c.email_address,

SUM(o.item_price * o.Quantity),

SUM(o.discount_amount * o.quantity)

FROM customer c

JOIN Order_Items o ON o.id = c.id

GROUP BY c.email_address

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4 years ago
IMPORTANT HELP
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Answer:

plz am so sorry I don't no it

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Plz give me brainiest

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